Userscripts.org

It's very simple, it is necessary to replace the code
calcUseShip(203, null);

var bt_lim0 = (evaluemax == 9000 ? 37 : 48);
var bt_lim1 = (evaluemax == 9000 ? 72 : 96);
var bt_lim9 = (evaluemax == 9000 ? 192 : 256);
var variant = 0;

if(c_getById(shipsNoSat, 203) >= bt_lim0) variant = 3;
if(c_getById(shipsNoSat, 203) >= bt_lim1) variant = 2;
if(c_getById(shipsNoSat, 203) >= bt_lim9) variant = 1;
switch (variant) {
case 1: {
break;
}
case 2: {
fillShips();
evalue = evaluemax;
calcUseShip(210, (evaluemax == 9000 ? 6 : 1));
calcUseShip(203, bt_lim1);
break;
}
case 3: {
fillShips();
evalue = evaluemax;
calcUseShip(210, 1);
calcUseShip(203, bt_lim0);
}
}
calcUseShip(203, null);
calcUseShip(202, null);
calcUseShip(205, null);
on this
calcUseShip(203, 48);
calcUseShip(205, null);
calcUseShip(202, null);

But then you'll never find more than 1.2 million metal.