Discussion on Website Styler | Userscripts.org

Archived Comments, replied by avg @ Sun, 28 Sep 2008 14:16:01 -0500

avg — Sun, 28 Sep 2008 14:16:01 -0500

Hey joe I improved my function:

$x=function() {
	for (var i=0;i<arguments.length;i++) {
		switch(typeof arguments[i]) {
			case "string":var x=arguments[i];break;
			case "number":var type=arguments[i];break;
			case "object":var node=arguments[i];break;
		}
	}
	return (!type) ? document.evaluate(x,(!node?document:node),null,9,null).singleNodeValue : document.evaluate(x,(!node?document:node),null,type,null)
};

It's overloaded and accepts arguments on type, not order. So $x(".//text()", document.links[0]) or $x(document.links[0],".//text()") would work.

Tell me if it works / needs more features please.

Assumptions:

That if the Result Type isn't supplied, you want to get the first result.
That if the Node isn't supplied, it will be checked against the document.

Archived Comments, replied by JoeSimmons @ Sun, 28 Sep 2008 12:50:32 -0500

JoeSimmons — Sun, 28 Sep 2008 12:50:32 -0500

Thanks. but actually I have one...

// XPath by JoeSimmons
function xp(_exp, t, n) {
var exp = _exp || "//*"; // XPath Expression
var type = t || 6; // XPath type (e.g., 6=unordered node snapshot)
var node = n || document; // XPath search node (only for advanced users; research it)
return(type==9)?document.evaluate(exp, node, null, 9, null).singleNodeValue:document.evaluate(exp, node, null, type, null);
}

So if I want one result, I can just do xp("id('some_id')",9);
If I want text inside of the first link, I do xp(".//text()", 9, document.links[0]);
If I want all tags, I just do xp();

Archived Comments, replied by avg @ Sun, 28 Sep 2008 10:52:11 -0500

avg — Sun, 28 Sep 2008 10:52:11 -0500

Joe, I made an overloaded XPath function, wanted to share it with you. Here it is:

$x=function(x,type) {
	return (!type) ? document.evaluate(x,document,null,9,null).singleNodeValue : document.evaluate(x,document,null,type,null)
};

So if you want only the first result, don't supply the second part:

$x("//div[@class='header']")

or if you want all the results, just specify the type:

$x("//div[@id='footer']//a",7)

Archived Comments, replied by JoeSimmons @ Mon, 01 Sep 2008 10:48:31 -0500

JoeSimmons — Mon, 01 Sep 2008 10:48:31 -0500

I want to do both. but I don't have much time lately. I will sometime.

Archived Comments, replied by avg @ Mon, 01 Sep 2008 08:36:38 -0500

avg — Mon, 01 Sep 2008 08:36:38 -0500

Yeah, instead of writing a greasemonkey script, you should just write the CSS for Stylish, then post it up on UserStyles.

Archived Comments, replied by Sebastian Paaske @ Sun, 27 Jul 2008 15:53:32 -0500

Sebastian Paaske — Sun, 27 Jul 2008 15:53:32 -0500

You should take a look at Stylish. ;)

Archived Comments, replied by nathaniel_higgins @ Wed, 25 Jun 2008 05:09:28 -0500

nathaniel_higgins — Wed, 25 Jun 2008 05:09:28 -0500

Seems nice! Thanks!

Archived Comments, replied by Jesse Andrews @ Tue, 16 Nov 2004 19:05:13 -0600

Jesse Andrews — Tue, 16 Nov 2004 19:05:13 -0600

The following is an archive of comments made before threaded discussions was implemented (November 16th, 2008)